-3(x^2+5x)=0

Solution for -3(x^2+5x)=0 equation:

-3(x^2+5x)=0

We multiply parentheses

-3x^2-15x=0

a = -3; b = -15; c = 0;
Δ = b2-4ac
Δ = -152-4·(-3)·0
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-15}{2*-3}=\frac{0}{-6}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+15}{2*-3}=\frac{30}{-6}
=-5
$